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	<title>Comments on: Backgammon, and the frequency of dice rolls</title>
	<link>http://oliverjenkins.com/2005/11/backgammon-and-the-frequency-of-dice-rolls/</link>
	<description>Oliver jenkins, my place on the web.  This site contains my projects and ideas across PHP, databases, XHTML / CSS and the web</description>
	<pubDate>Thu, 28 Aug 2008 02:13:22 +0000</pubDate>
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		<title>by: oli jenks</title>
		<link>http://oliverjenkins.com/2005/11/backgammon-and-the-frequency-of-dice-rolls/#comment-639</link>
		<pubDate>Mon, 05 Feb 2007 18:54:31 +0000</pubDate>
		<guid>http://oliverjenkins.com/2005/11/backgammon-and-the-frequency-of-dice-rolls/#comment-639</guid>
					<description>Your right of course.  Bit of an embarrassment really, but it appears that I forgot about doubles counting twice.  Will re-calculate when I get a moment.

Oliver</description>
		<content:encoded><![CDATA[Your right of course.  Bit of an embarrassment really, but it appears that I forgot about doubles counting twice.  Will re-calculate when I get a moment.

Oliver
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		<title>by: john</title>
		<link>http://oliverjenkins.com/2005/11/backgammon-and-the-frequency-of-dice-rolls/#comment-627</link>
		<pubDate>Sun, 04 Feb 2007 17:33:23 +0000</pubDate>
		<guid>http://oliverjenkins.com/2005/11/backgammon-and-the-frequency-of-dice-rolls/#comment-627</guid>
					<description>I think your calculations are incorrect.  It may be my understanding of what you are trying to show.  

I think 11 is equally common as 12 and 1 should be much, much more common.  The way I am thinking, all the rolls less than 7 would be more common than those requiring two dice, though I can't immediately prove either completely.  

A roll of 11 must be a 5-6 or 6-5, or two possibilities of the 36 possible outcomes.  A roll of 12 can be 6-6 or 4-4, also 2 of 36.  Wouldn't they have equal probability?  Your chart, however shows 10 as more likely than 1.

A roll of 10 can be 6-4, 4-6, or 5-5, but a move of 1 can result from any of the 11 outcomes with a 1 showing, 1-* and *-1, minus 1-1 so it isn't counted twice.</description>
		<content:encoded><![CDATA[I think your calculations are incorrect.  It may be my understanding of what you are trying to show.  

I think 11 is equally common as 12 and 1 should be much, much more common.  The way I am thinking, all the rolls less than 7 would be more common than those requiring two dice, though I can&#8217;t immediately prove either completely.  

A roll of 11 must be a 5-6 or 6-5, or two possibilities of the 36 possible outcomes.  A roll of 12 can be 6-6 or 4-4, also 2 of 36.  Wouldn&#8217;t they have equal probability?  Your chart, however shows 10 as more likely than 1.

A roll of 10 can be 6-4, 4-6, or 5-5, but a move of 1 can result from any of the 11 outcomes with a 1 showing, 1-* and *-1, minus 1-1 so it isn&#8217;t counted twice.
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